TypeError: Argument of Type ‘int’ is not Iterable
So you’re getting the TypeError: argument of type ‘int’ is not iterable error message. I came across this issue when calling an api, extracting some data from a json object, and trying to determine if I needed to do something with that info.
Bite Size Soln for Those in a Rush
In short, you’re trying to find whether a substring exists in an integer. Make sure to cast your ints to strings and you should be able to continue on your way. Now, if you’d like a more detailed explanation, continue on.
You are inadvertently trying to determine if a substring is in an integer! Let’s recreate it in a line or two.
word = 'stuff' blur = 12344566 word in blur
You should be greeted with the ugly, “TypeError: argument of type ‘int’ is not iterable” message.
Cast, Cast, Cast.
word = 'stuff' blur = 12344566 word in str(blur)
A More Realistic Example
This will output false successfully telling you whether stuff can be found within the now string ‘12344566’. And now for a more realistic example.
array = ['Foo','Bar', 1] for element in array: print(element) if 'sandwich' in element: print('Found the sandwich')
Here we can see all elements of the array are printed because the error occurs on the third element. One will never find a string in an int. You can avoid checking types and error handling by wrapping element in str() to cast it as a string in case we come across any unruly data types.
array = ['Foo','Bar', 1] for element in array: print(element) if 'sandwich' in str(element): print('Found the sandwich')
The problem is gone. We also never find the sandwich. Happy coding!